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UTME Chemistry 1987 JAMB Past Questions and Answers, Jamb, Pre-degree, Nursing, Waec, Neco

UTME Chemistry 1987 JAMB Past Questions and Answers, Jamb, Pre-degree, Nursing, Waec, Neco

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UTME Chemistry 1987 JAMB Past Questions and Answers

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Temp (°C)253545
Time (seconds)723618

1. The times taken for iodine to be liberated in the reaction between sodium thiosulphate and hydrochloric acid at various temperature are as follows. These results suggest that

Options

A) for a 10o rise in temperature, rate of reaction is double

B) for a 10 o rise in temperature, rate of reaction is halved

C) time taken for iodine to appear does not depend on temperature

D) for a 10 o rise in temperature rate of reaction is tripled

The correct answer is A.

2. If 24.83 cm3 of 0.15 M NaOH is titrated to its end point with 39.45 cm3 of HCl, what is the molarity of the HCl?

Options

A) 0.094 M

B) 0.150 M

C) 0.940 M

D) 1.500 M

The correct answer is A.

Explanation:

NaOH + HCl → NaCl + H2O moles ratio = 1/1
↔ (MaVa) / Mb x 39.45 = 0.094

3. The atomic numbers of two elements X and Y are 12 and 19 respectively. The bond of these two elements is?

Options

A) ionic

B) covalent

C) neutral

D) co-ordinate

The correct answer is B.

4. If d represents the density of a gas and K is a constant, the rate of gaseous diffusion r is related to d by the equation?

Options

A) r = k/√d

B) r = kd

C) r =k/d

D) r = k √d

The correct answer is A.

Explanation:

r = k /√d

5. An isotope has an atomic number of 17 and a mass number of 36. Which of the following gives the correct number of neutrons and protons in an atom of the isotope?

Options

A) Neutrons 53, Protons 17

B) Neutrons 17, Protons 36

C) Neutrons 19, Protons 17

D) Neutrons 36, Protons 17

The correct answer is C.

Explanation:

Mass number = number of protons + number of neutrons
36 = 17 + X; X = 36 -17 = 19
19 neutrons and 17 protons

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